javascript的加减乘除函数

2022-02-28

    function accDiv(arg1, arg2) {
        var t1 = 0, t2 = 0, r1, r2;
        try {
            t1 = arg1.toString().split('.')[1].length
        } catch (e) {
        }
        try {
            t2 = arg2.toString().split('.')[1].length
        } catch (e) {
        }
        with (Math) {
            r1 = Number(arg1.toString().replace('.', ''));
            r2 = Number(arg2.toString().replace('.', ''));
            return (r1 / r2) * pow(10, t2 - t1);
        }
    }
    function accMul(arg1, arg2)
    {
        var m = 0, s1 = arg1.toString(), s2 = arg2.toString();
        try {
            m += s1.split('.')[1].length
        } catch (e) {
        }
        try {
            m += s2.split('.')[1].length
        } catch (e) {
        }
        return Number(s1.replace('.', '')) * Number(s2.replace('.', '')) / Math.pow(10, m);
    }
    function accAdd(arg1, arg2) {
        var r1, r2, m;
        try {
            r1 = arg1.toString().split('.')[1].length
        } catch (e) {
            r1 = 0
        }
        try {
            r2 = arg2.toString().split('.')[1].length
        } catch (e) {
            r2 = 0
        }
        m = Math.pow(10, Math.max(r1, r2));
        return (arg1 * m + arg2 * m) / m;
    }
    function accSub(arg1, arg2) {
        var r1, r2, m, n;
        try {
            r1 = arg1.toString().split('.')[1].length
        } catch (e) {
            r1 = 0
        }
        try {
            r2 = arg2.toString().split('.')[1].length
        } catch (e) {
            r2 = 0
        }
        m = Math.pow(10, Math.max(r1, r2));
        //动态控制精度长度
        n = (r1 >= r2) ? r1 : r2;
        return ((arg2 * m - arg1 * m) / m).toFixed(n);
    }
  

联系信息

QQ:1827566828
Email: 1827566828@qq.com
Web: https://www.yynet.wang

留言